NAME
	IEEEDPSub -- subtract one double precision IEEE number from another

   SYNOPSIS
	  x   = IEEEDPSub(  y  ,  z  );
	d0/d1		  d0/d1 d2/d3

	double	x,y,z;

   FUNCTION
	Compute x = y - z in IEEE double precision.

   INPUTS
	y -- IEEE double precision floating point value
	z -- IEEE double precision floating point value

   RESULT
	x -- IEEE double precision floating point value

   BUGS

   SEE ALSO
	IEEEDPAdd()